Giải thích các bước giải:
Đặt `x/3=y/4=k`
`x/3=k=>x=3k`
`y/4=k=>y=4k`
Lại có:
`x.y=48`
`=>3k4k=48`
`=>12k^2=48`
`=>k^2=48:12`
`=>k^2=4`
`=>`\(\left[ \begin{array}{l}k^2=2^2\\k^2=(-2)^2\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}k=2\\k=-2\end{array} \right.\)
`TH1:k=2`
`x=3.2=6`
`y=2.4=8`
`TH2:k=-2`
`x=-2.3=-6`
`y=-2.4=-8`
Vậy `x=6;y=8`
`x=-6;y=-8`