Em tham khảo nha:
\(\begin{array}{l}
3)\\
a)\\
F > O > N > P\\
b)\\
\text{ Hiện tượng: Quỳ tím mất màu}\\
C{l_2} + 2NaOH \to NaCl + NaClO + {H_2}O\\
4)\\
a)\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
b)\\
{n_{{H_2}}} = \dfrac{{3,36}}{{22,4}} = 0,15\,mol\\
{n_{Zn}} = {n_{{H_2}}} = 0,15\,mol\\
{m_{Zn}} = 65 \times 0,15 = 9,75g\\
{n_{HCl}} = 2{n_{{H_2}}} = 0,3\,mol\\
{C_M}HCl = \dfrac{{0,3}}{{0,1}} = 3M
\end{array}\)