` n+15 \vdots n+3`
`to( n+3)+12 \vdots n+3`
`to12 \vdots n+3`
`ton+3in Ư_((12))={+-1;+-2;+-3;+-4;+-6;+-12}`
$\left[\begin{array}{ccc}n+3&-12&-6&-4&-3&-2&-1&1&2&3&4&6&12\\n&-15&-9&-7&-6&-5&-4&-2&-1&0&1&3&9\end{array}\right]\\\text{Vậy n $\in${-15 ; ±9 ; -7 ; -6 ; -5 ; -4 ; -2 ; ±1 ; 3 }}$
`\text{@}\bb{Ngọc Châu}`