Em tham khảo nha:
\(\begin{array}{l}
1)\\
a)\\
CuC{l_2} + 2NaOH \to Cu{(OH)_2} + 2NaCl\\
b)\\
{n_{CuC{l_2}}} = 0,1 \times 2 = 0,2\,mol\\
{n_{NaOH}} = 2{n_{CuC{l_2}}} = 0,4\,mol\\
{m_{{\rm{dd}}NaOH}} = \dfrac{{0,4 \times 40}}{{20\% }} = 80g\\
c)\\
{n_{Cu{{(OH)}_2}}} = {n_{CuC{l_2}}} = 0,2\,mol\\
Cu{(OH)_2} \xrightarrow{t^0} CuO + {H_2}O\\
{n_{CuO}} = {n_{Cu{{(OH)}_2}}} = 0,2\,mol\\
{m_{CuO}} = 0,2 \times 80 = 16g\\
2)\\
a)\,K > Na > Mg > Al > Fe > Cu > Ag\\
b)\\
2K + 2{H_2}O \to 2KOH + {H_2}\\
2KOH + CuC{l_2} \to Cu{(OH)_2} + 2KCl\\
2Na + 2{H_2}O \to 2NaOH + {H_2}\\
2NaOH + CuC{l_2} \to Cu{(OH)_2} + 2NaCl\\
Mg + CuC{l_2} \to Cu + MgC{l_2}\\
2Al + 3CuC{l_2} \to 2AlC{l_3} + 3Cu\\
Fe + CuC{l_2} \to Cu + FeC{l_2}
\end{array}\)