`B=2x-2x^2+3=-(2x^2-2x-3)`
`=-( (\sqrt2x)^2 - 2. \sqrt2x . \sqrt2/2 + (\sqrt2/2)^2)+7/2`
`=-(\sqrt2 x - \sqrt2/2)^2 +7/2`
Vì `-(\sqrt2 x -\sqrt2/2)^2 ≤0 \forall x => -(\sqrt2 x-\sqrt2/2)^2 +7/2 ≤ 7/2`
`=> B_(Max)=7/2 <=> \sqrt2 x-\sqrt2/2 = 0<=> x=1/2`