Đáp án:
\(\left[ \begin{array}{l}
x = 0\\
x = 2
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
\left| {5x - 1} \right| + \left| {3 - 2x} \right| = \left| {4 + 3x} \right|\\
\to \left[ \begin{array}{l}
5x - 1 + 3 - 2x = 4 + 3x\left( {DK:\dfrac{3}{2} \ge x \ge \dfrac{1}{5}} \right)\\
- 5x + 1 + 3 - 2x = 4 + 3x\left( {DK:\dfrac{1}{5} > x} \right)\\
5x - 1 - 3 + 2x = 4 + 3x\left( {DK:x > \dfrac{3}{2}} \right)
\end{array} \right.\\
\to \left[ \begin{array}{l}
2 = 4\left( l \right)\\
10x = 0\\
4x = 8
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 0\left( {TM} \right)\\
x = 2\left( {TM} \right)
\end{array} \right.
\end{array}\)
