Đáp án:
$D.\, 2\pi$
Giải thích các bước giải:
$3\cos x - 1 = 0$
$\Leftrightarrow \cos x = \dfrac13$
$\Leftrightarrow x =\pm \arccos\dfrac13 + k2\pi\quad (k\in\Bbb Z)$
Ta có:
$\quad 0 < x < 2\pi$
$\to 0 < \pm \arccos\dfrac13 + k2\pi< 2\pi$
$\to \left[\begin{array}{l}k = 0\\k = 1\end{array}\right.$
$\to \left[\begin{array}{l}x = \arccos\dfrac13\\x = 2\pi -\arccos\dfrac{1}{3}\end{array}\right.$
$\to S = \arccos\dfrac13 + 2\pi - \arccos\dfrac13 = 2\pi$