Đáp án:
\(\begin{array}{l} b,\ V_{H_2}=2,24\ (l).\\ c,\ C_{M_{\text{dd H$_2$SO$_4$}}}=2\ (M).\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l} a,\\ PTHH:Fe+H_2SO_4\to FeSO_4+H_2\uparrow\\ b,\\ n_{Fe}=\dfrac{5,6}{56}=0,1\ (mol).\\ Theo\ pt:\ n_{H_2}=n_{Fe}=0,1\ (mol).\\ \Rightarrow V_{H_2}=0,1\times 22,4=2,24\ (l).\\ c,\\ Theo\ pt:\ n_{H_2SO_4}=n_{Fe}=0,1\ (mol).\\ V_{\text{dd H$_2$SO$_4$}}=50\ (ml)=0,05\ (l).\\ \Rightarrow C_{M_{\text{dd H$_2$SO$_4$}}}=\dfrac{0,1}{0,05}=2\ (M).\end{array}\)
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