Câu 29:
a,
$2H_2+O_2\buildrel{{t^o}}\over\to 2H_2O$
$2CO+O_2\buildrel{{t^o}}\over\to 2CO_2$
b,
Gọi $x$, $y$ là số mol $H_2$, $CO$
$\Rightarrow 2x+28y=13,6$ $(1)$
$n_{O_2}=\dfrac{17,92}{22,4}=0,8(mol)$
$\Rightarrow 0,5x+0,5y=0,8$ $(2)$
$(1)(2)\Rightarrow x=1,2; y=0,4$
$m_{H_2}=1,2.2=2,4g$
$m_{CO}=0,4.28=11,2g$
c,
$\%V_{H_2}=\dfrac{1,2.100}{1,2+0,4}=75\%$
$\%V_{CO}=25\%$
