Đặt $\frac{1}{2x-y}=a; \frac{1}{x-2y}=b$
Hệ pt trở thành :$ \left\{\begin{matrix}
2a+3b=\frac{1}{2} & \\
2a-b=\frac{1}{18} &
\end{matrix}\right.\Leftrightarrow \left\{\begin{matrix}
2a+3b=\frac{1}{2} & \\
4b=\frac{4}{9}&
\end{matrix}\right.=> b=\frac{1}{9}; a=\frac{1}{12}=> \left\{\begin{matrix}
2x-y=12 & \\
x-2y=9 &
\end{matrix}\right.\Leftrightarrow \left\{\begin{matrix}
2x-y=12 & \\
2x-4y=18&
\end{matrix}\right.\Leftrightarrow x=5;y=-2(t/m)$
