Đáp án:
\(\begin{array}{l}
b)\\
{m_{Cu}} = 1,6g\\
c)\\
{C_{{M_{{H_2}S{O_4}}}}} = 0,75M
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
Fe + {H_2}S{O_4} \to FeS{O_4} + {H_2}\\
b)\\
{n_{{H_2}}} = \frac{V}{{22,4}} = \dfrac{{3,36}}{{22,4}} = 0,15mol\\
{n_{Fe}} = {n_{{H_2}}} = 0,15mol\\
{m_{Fe}} = 0,15 \times 56 = 8,4g\\
{m_{Cu}} = 10 - 8,4 = 1,6g\\
c)\\
{n_{{H_2}S{O_4}}} = {n_{{H_2}}} = 0,15mol\\
{C_{{M_{{H_2}S{O_4}}}}} = \dfrac{{0,15}}{{0,2}} = 0,75M
\end{array}\)