Đáp án:
$x^2+5x-10=(x+\dfrac{5-\sqrt{65}}{2})(x+\dfrac{5+\sqrt{65}}{2})$
Giải thích các bước giải:
$x^2+5x-10$
$=x^2+5x+\dfrac{25}{4}-\dfrac{25}{4}-10$
$=x^2+2 . x. \dfrac{5}{2}+(\dfrac{5}{2})^2-\dfrac{65}{4}$
$=(x+\dfrac{5}{2})^2-(\dfrac{\sqrt{65}}{2})^2$
$=(x+\dfrac{5}{2}-\dfrac{\sqrt{65}}{2})(x+\dfrac{5}{2}+\dfrac{\sqrt{65}}{2})$
$=(x+\dfrac{5-\sqrt{65}}{2})(x+\dfrac{5+\sqrt{65}}{2})$