`2^x + 3. 2^(x+2) = 39 - 2^(x - 1)`
`⇒ 2^x + 3. 2^(x+2) + 2^(x - 1) = 39`
`⇒ 2^x + 3. 2^x. 2^2 + 2^x : 2 = 39`
`⇒ 2^x + 3. 2^x. 4 + 2^x. 1/2 = 39`
`⇒ 2^x + 2^x. 12 + 2^x. 1/2 = 39`
`⇒ 2^x. (1 + 12 + 1/2) = 39`
`⇒ 2^x. 27/2 = 39`
`⇒ 2^x = 39 : 27/2`
`⇒ 2^x = 26/9`
`⇒ x ∈ ∅`