Đáp án:
`|x - 5| - (-3) = 9`
`|x - 5| + 3 = 9`
`|x - 5| = 9 - 3`
`|x - 5| = 7`
`⇔` \(\left[ \begin{array}{l}x-5=7\\x - 5 = - 7\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x= 7+5\\x = - 7+5\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x=12\\x = - 2\end{array} \right.\)
Vậy `x ∈ {12 ; -2}`
`135 - |9 - x| = 35`
`|9 - x| = 135 - 35`
`|9 - x| = 100`
`⇔` \(\left[ \begin{array}{l}9-x = 100\\9-x=-100\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x = 9 - 100\\x = 9 + 100\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x= -91\\x=109\end{array} \right.\)
Vậy `x ∈ {-91 ; 109}`
`(x +2) . 5 = 1024`
`x + 2 = 1024 : 5`
`x + 2 = 204,8`
`x = 204,8 - 2`
`x = 202,8`
Vậy `x = 202,8`
`2^{2x - 1} : 4 = 8`
`2^{2x - 1} = 8 . 4`
`2^{2x - 1} = 32`
`2^{2x - 1} = 2^5`
`⇒ 2x - 1 = 5`
`2x = 5 + 1`
`2x = 6`
`x = 6 : 2`
`x = 3`
Vậy `x = 3`
`(x - 5) . (x^2 - 4) = 0`
`⇔` \(\left[ \begin{array}{l}x - 5 = 0\\x^2 - 4 = 0\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x = 0 + 5\\x^2 = 0+4\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x = 5\\x^2 = 4\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x = 5\\x^2 = 2^2\end{array} \right.\)
`⇔`\(\left[ \begin{array}{l}x = 5\\⇒x = 2\end{array} \right.\)
Vậy `x ∈ {5 ; 2}`
