Ta có: `{x+2}/{y-7}={11}/2` $(ĐK:y\ne 7)$
`=>2.(x+2)=11.(y-7)`
`=>2x+4=11y-77`
`=>2x=11y-77-4`
`=>2x=11y-81`
Ta lại có `2x+y=27`
`=>(11y-81)+y=27`
`=>11y+y=27+81`
`=>12y=108`
`=>y=108:12`
`=>y=9` thay vào $2x=11y-81$ ta có:
`\qquad 2x=11.9-81`
`=>2x=99-81`
`=>2x=18`
`=>x=9`
Vậy $x=9;y=9$