Bài làm :
`(x^2 – 4) + (x – 2)(3 – 2x) = 0`
`⇔ (x – 2)(x + 2) + (x – 2)(3 – 2x) = 0`
`⇔ (x – 2)[(x + 2) + (3 – 2x)] = 0`
`⇔ (x – 2)(5 – x) = 0`
⇔ \(\left[ \begin{array}{l}x-2=0\\5-x=0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x-2=0\\5-x=0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=2\\x=5\end{array} \right.\)
Vậy `..............`