Đáp án:
a) -2
Giải thích các bước giải:
\(\begin{array}{l}
a)\left[ {6.{{\left( { - \dfrac{1}{3}} \right)}^2} - 3\left( { - \dfrac{1}{3}} \right) + 1} \right]:\left( { - \dfrac{1}{3} - 1} \right)\\
= \left( {\dfrac{2}{3} + 1 + 1} \right):\left( { - \dfrac{4}{3}} \right)\\
= \dfrac{8}{3}.\left( { - \dfrac{3}{4}} \right) = - 2\\
b)\dfrac{{{{\left( {\dfrac{2}{3}} \right)}^3}.{{\left( { - \dfrac{3}{4}} \right)}^2}.{{\left( { - 1} \right)}^{2003}}}}{{{{\left( {\dfrac{2}{5}} \right)}^2}.{{\left( { - \dfrac{5}{{12}}} \right)}^3}}}\\
= \dfrac{{\dfrac{8}{{27}}.\dfrac{9}{{16}}.\left( { - 1} \right)}}{{\dfrac{4}{{25}}.\dfrac{{ - 125}}{{1728}}}} = \dfrac{1}{6}:\dfrac{5}{{432}} = \dfrac{{72}}{5}
\end{array}\)
