Đáp án:
\(x = - \dfrac{{10}}{7}\)
Giải thích các bước giải:
\(\begin{array}{l}
\left| {2x - 1} \right| - 3\left| {x + 2} \right| = 2x + 5\\
\to \left[ \begin{array}{l}
2x - 1 - 3\left( {x + 2} \right) = 2x + 5\left( {DK:x \ge \dfrac{1}{2}} \right)\\
- 2x + 1 - 3\left( {x + 2} \right) = 2x + 5\left( {DK:\dfrac{1}{2} > x \ge - 2} \right)\\
- 2x + 1 + 3\left( {x + 2} \right) = 2x + 5\left( {DK:x < - 2} \right)
\end{array} \right.\\
\to \left[ \begin{array}{l}
2x - 1 - 3x - 6 = 2x + 5\\
- 2x + 1 - 3x - 6 = 2x + 5\\
- 2x + 1 + 3x + 6 = 2x + 5
\end{array} \right.\\
\to \left[ \begin{array}{l}
- 3x = 2\\
7x = - 10\\
x = 2\left( {KTM} \right)
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = - \dfrac{2}{3}\left( {KTM} \right)\\
x = - \dfrac{{10}}{7}\left( {TM} \right)
\end{array} \right.\\
KL:x = - \dfrac{{10}}{7}
\end{array}\)
