Đáp án:
$\dfrac{2}{x-2}$
Giải thích các bước giải:
$($ $\dfrac{14}{x^2 - 4}$ $+$ $\dfrac{x - 3}{x-2}$ $- $ $\dfrac{x-1}{x+2}$ $)$ $: ($ $\dfrac{1}{x+2}$ $ + 1$ $) $
⇔$($ $\dfrac{14 +x^2 - x - 6 - x^2 + 3x - 2}{(x - 2 ) ( x +2 )}$ $)$ : $\dfrac{x + 3}{x+2}$
⇔ $\dfrac{2x + 6}{( x - 2 ) ( x + 2 )}$ . $\dfrac{x+2}{x+3}$
⇔$\dfrac{2( x + 3)}{x-2}$ . $\dfrac{1}{x+3}$
⇔$\dfrac{2}{x-2}$
