`ĐKXĐ: x\ge 1/2`
`2\sqrt(2x-1)+\sqrt(x+3)-\sqrt(5x+11)=0`
`⇔2\sqrt(2x-1)+\sqrt(x+3)=\sqrt(5x+11)`
`⇔4(2x-1)+x+3+4\sqrt[(2x-1)(x+3)]=5x+11`
`⇔4\sqrt[(2x-1)(x+3)]=12-4`
`⇔\sqrt[(2x-1)(x+3)]=3-x`
`⇔2x^2+5x-3=x^2-6x+9`
`⇔x^2+11x-12=0`
`⇔(x-1)(x+12)=0`
\(⇔\left[ \begin{array}{l}x=1\\x=-12(l)\end{array} \right.\)
Vậy `x=1`