`1) (3x-2)(4x+5)= 0`
`⇔` \(\left[ \begin{array}{l}3x-2=0\\4x+5=0\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x=\dfrac{2}{3}\\x=-\dfrac{5}{4}\end{array} \right.\)
Vậy `S={2/3;-5/4}`
`2)(2,3x-6,9)(0,1x+2)= 0`
`⇔` \(\left[ \begin{array}{l}2,3x-6,9=0\\0,1x+2=0\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x=3\\x=20\end{array} \right.\)
Vậy `S={3;20}`