Tham khảo
` c) x+\frac{1}{2}=2^5:2^3`
`⇒x+\frac{1}{2}=2^2`
`⇒x+\frac{1}{2}=4`
`⇒x=4-\frac{1}{2}`
`⇒x=\frac{7}{2}`
`d) (x+\frac{1}{2})^2=\frac{4}{25}`
`⇒(x+\frac{1}{2})^2=(\frac{2}{5})^2`
`⇒`\(\left[ \begin{array}{l}x+\dfrac{1}{2}=\dfrac{2}{5}\\x+\dfrac{1}{2}=\dfrac{-2}{5}\end{array} \right.\)
`⇒`\(\left[ \begin{array}{l}x=\dfrac{2}{5}-\dfrac{1}{2}\\x=\dfrac{-2}{5}-\dfrac{1}{2}\end{array} \right.\)
`⇒`\(\left[ \begin{array}{l}x=\dfrac{-1}{10}\\x=\dfrac{-9}{10}\end{array} \right.\)
Vậy `x=\frac{-1}{10}` hoặc `x=\frac{-9}{10}`
