Đáp án:
Giải thích các bước giải:
`a)`
`(n+3)/(n-1) in ZZ`
`<=> n+3 vdots n-1`
`=> n-1+4 vdots n-1`
`=> 4 vdots n-1`
`=> n-1 in Ư(4)`
`=> n-1 in {-4;-2;-1;1;2;4}`
`=> n in {-3;-1;0;2;3;5}`
`b)`
`(n+1)/(2n-1) in ZZ`
`<=> n+1 vdots 2n-1`
`=> 2n+2 vdots 2n-1`
`=> 2n-1+3 vdots 2n-1`
`=> 3 vdots 2n-1`
`=> 2n-1 in Ư(3)={-3;-1;1;3}`
`=> 2n in {-2;0;2;4}`
`=> n in {-1;0;1;2}`