Đáp án:
a, `x=-\frac{15}{16}`
b, `x=-3`
c, `x=-\frac{8}{45}`
d, `x∈{\frac{5}{6};5}`
Giải thích các bước giải:
a,`\frac{5}{4}:x+2=\frac{2}{3}`
`⇒\frac{15}{4}+6x=2x`
`⇒4x=-\frac{15}{4}`
`⇒x=-\frac{15}{16}`
Vậy `x=-\frac{15}{16}`
b, `\frac{4}{9}+\frac{5}{6}:x=\frac{1}{6}`
`⇒\frac{5}{6}:x=\frac{5}{18}`
`⇒x=-3`
Vậy `x=-3`
c, `3x+\frac{1}{5}=-\frac{2}{6}`
`⇒3x=-\frac{8}{15}`
`⇒x=-\frac{8}{45}`
Vậy `x=-\frac{8}{45}`
d, `(\frac{3}{5}x-\frac{1}{2})(\frac{x+1}{-9}+\frac{-2}{-3})=0`
`⇒`\(\left[ \begin{array}{l}\dfrac{3}{5}x-\dfrac{1}{2}=0\\\dfrac{-x-1}{9}+\dfrac{2}{3}=0\end{array} \right.\)
`⇒`\(\left[ \begin{array}{l}\dfrac{3}{5}x=\dfrac{1}{2}\\-x-1+6=0\end{array} \right.\)
`⇒`\(\left[ \begin{array}{l}x=\dfrac{5}{6}\\x=5\end{array} \right.\)
Vậy `x∈{\frac{5}{6};5}`
