Em tham khảo nha:
\(\begin{array}{l}
1)\\
S + {O_2} \xrightarrow{t^0} S{O_2}( \text{ Lưu huỳnh dioxit})\\
4P + 5{O_2} \xrightarrow{t^0} 2{P_2}{O_5}(diphotpho\,pentaoxit)\\
3Fe + 2{O_2} \xrightarrow{t^0} F{e_3}{O_4} \text{ Oxit sắt từ }\\
2Mg + {O_2} \xrightarrow{t^0} 2MgO(Magie\,{\rm{ox}}it)\\
2)\\
{\rm{Ox}}itbazo\\
N{a_2}O:Natri\,{\rm{ox}}it\\
MgO:Magie\,\,oxit\\
{\rm{Ox}}it{\rm{ax}}it\\
C{O_2}:Cacbon\,dioxit\\
S{O_2}: \text{ Lưu huỳnh dioxit}\\
{P_2}{O_5}:diphotpho\,pentaoxit\\
3)\\
a)\\
2Mg + {O_2} \xrightarrow{t^0} 2MgO\\
{n_{Mg}} = \dfrac{{4,8}}{{24}} = 0,2\,mol\\
{n_{{O_2}}} = \dfrac{{0,2}}{2} = 0,1\,mol\\
{V_{{O_2}}} = 0,1 \times 22,4 = 2,24l\\
b)\\
2KMn{O_4} \to {K_2}Mn{O_4} + Mn{O_2} + {O_2}\\
{n_{KMn{O_4}}} = 0,1 \times 2 = 0,2\,mol\\
{m_{KMn{O_4}}} = 0,2 \times 158 = 31,6g
\end{array}\)
