Đáp án + Giải thích các bước giải:
`|2x-1|=1-2x` `(ĐK:1-2x≥0->x≤(1)/(2))`
`⇒` \(\left[ \begin{array}{l}2x-1=1-2x\\2x-1=-(1-2x)\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}2x+2x=1+1\\2x-1=-1+2x\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}4x=2\\2x-2x=1-1\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}x=\frac{1}{2}(TM)\\0x=0\text{(Luôn đúng)}\end{array} \right.\)
`⇒` Với mọi `x≤(1)/(2)` thì `|2x-1|=1-2x`
`------------`
`|x+1|-3=x-2` `(x≥-1)`
`⇒|x+1|=x-2+3`
`⇒|x-1|=x+1`
`⇒` \(\left[ \begin{array}{l}x-1=x+1\text{ ( Vô Lí )} \\x-1=-(x+1)\end{array} \right.\)
`⇒x-1=-x-1`
`⇒x+x=1-1`
`⇒2x=0`
`⇒x=0(TM)`
Vậy `x=0`
