Đáp án+Giải thích các bước giải:
`g,2\sqrt{3}x^2+x+1=\sqrt{3}x+1`
`<=>2\sqrt{3}x^2+x(1-\sqrt{3})=0`
`\Delta=(\sqrt{3}-1)^2`
`=>\sqrt{\Delta}=\sqrt{3}-1`
`=>x_1=(\sqrt{3}-1+\sqrt{3}-1)/(4\sqrt{3})=(3-\sqrt{3})/6,x_2=(\sqrt{3}-1+1-\sqrt{3})/(4\sqrt{3})=0`
`m,x^2-2\sqrt{3}-x-2\sqrt{3}=0`
`<=>x^2-x-4\sqrt{3}=0`
`\Delta=1+16\sqrt{3}`
`=>\Delta=\sqrt{16\sqrt{3}+1}`
`=>x_1=(1+\sqrt{16\sqrt{3}+1})/2,x_2=(1-\sqrt{16\sqrt{3}+1})/2`
