Đáp án:
↓↓↓
Giải thích các bước giải:
`a,|-2x|-3x=4`
⇒`2|x|-3x=4`
⇒\(\left[ \begin{array}{l}2x-3x=4(x≥0)\\2(-x)-3x=4(x<0)\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x∈∅\\x=-4/5\end{array} \right.\)
Vậy `x=-4/5`
`b,|3x-1|=x-2`
⇒`|3x-1|-x=-2`
⇒\(\left[ \begin{array}{l}3x-1=-2(3x-1≥0)\\-(3x-1)-x=-2(3x-1<0)\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x∈∅\\x∈∅\end{array} \right.\)
