Đáp án + Giải thích các bước giải:
`4x-|3x-2|=5` `(ĐK:4x-5≥0=>x≥(5)/(4))`
`⇔|3x-2|=4x-5`
`⇔` \(\left[ \begin{array}{l}3x-2=4x-5\\3x-2=-4x+5\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}3x-4x=2-5\\3x+4x=2+5\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}-x=-3\\7x=7\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x=3(TM)\\x=1(KTM)\end{array} \right.\)
Vậy `S={3}`
