Đáp án:
Giải thích các bước giải:
`a,(1+x)/(2x-1)=(3x-2)/(6x+3)`
`⇒(1+x)(6x+3)=(2x-1)(3x-2)`
`⇔6x+3+6x^2+3x=6x^2-4x-3x+2`
`⇔16x=-1`
`⇔x=-1/16`
Vậy `x=-1/16`
`b,(4x-1)/(3x+4)=(8x-2)/(2+6x)`
`⇒(4x-1)(2+6x)=(8x-2)(3x+4)`
`⇔8x+24x^2-2-6x=24x^2+32x-6x-8`
`⇔-24x=-6`
`⇔x=1/4`
Vậy `x=1/4`
`c,1/(x-2)+3=(7-x)/(x-2)`
`⇔(1+3x-6)/(x-2)=(7-x)/(x-2)`
`⇒3x-5=7-x`
`⇔4x=12`
`⇔x=3`
Vậy `x=3`
`d,(2-3x)/(1+3x)-1=(-4x-3)/(2x+1)`
`⇔(2-3x-1-3x)/(1+3x)=(-4x-3)/(2x+1)`
`⇔(-6x+1)/(1+3x)=(-4x-3)/(2x+1)`
`⇒(-6x+1)(2x+1)=(1+3x)(-4x-3)`
`⇔-12x^2-6x+2x+1=-4x-3-12x^2-9x`
`⇔9x=-4`
`⇔x=-4/9`
Vậy `x=-4/9`
