Đáp án + Giải thích các bước giải:
`a//(10)/(x+5)=(7x+1)/(x+5)-3` `(ĐKXĐ:x\ne-5)`
`⇔(10)/(x+5)=(7x+1)/(x+5)-(3(x+5))/(x+5)`
`⇔7x+1-3(x+5)=10`
`⇔7x+1-3x-15=10`
`⇔7x-3x=-1+15+10`
`⇔4x=24`
`⇔x=6(TM)`
Vậy `S={6}`
`b//|3-5x|=2x+1` `( ĐK:x≥-\frac{1}{2})`
`⇔` \(\left[ \begin{array}{l}3-5x=2x+1\\3-5x=-2x-1\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}-5x-2x=-3+1\\-5x+2x=-3-1\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}-7x=-2\\-3x=-4\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x=\frac{2}{7}(TM)\\x=\frac{4}{3}(TM)\end{array} \right.\)
Vậy `S={(2)/(7);(4)/(3)}`
