Đáp án:
Ta có:
$\begin{array}{l}
\dfrac{{MN}}{{KH}} = \dfrac{2}{6} = \dfrac{1}{3}\\
\dfrac{{MP}}{{KQ}} = \dfrac{5}{{15}} = \dfrac{1}{3}\\
\dfrac{{NP}}{{HQ}} = \dfrac{6}{{18}} = \dfrac{1}{3}\\
\Rightarrow \dfrac{{MN}}{{KH}} = \dfrac{{MP}}{{KQ}} = \dfrac{{NP}}{{HQ}} = \dfrac{1}{3}\\
\Rightarrow \Delta MNP \sim \Delta KHQ\left( {c - c - c} \right)\\
\Rightarrow \left\{ \begin{array}{l}
\widehat {MNP} = \widehat {KHQ}\\
\widehat {NMP} = \widehat {HKQ}
\end{array} \right.
\end{array}$
