Đáp án:
a) 5(2x-1) - x(2x-1) = 0
⇔ (5-x)(2x-1)=0
⇔\(\left[ \begin{array}{l}5-x=0\\2x-1=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=5\\x=1/2\end{array} \right.\)
b) $\frac{2x^{2}-4x}{x(x+5)}$ = 0
⇔ 2$x^{2}$ -4x = 0
⇔2x(x-2)=0
⇔\(\left[ \begin{array}{l}x=0\\x=2\end{array} \right.\)
c) $\frac{-(x+2)^2}{(x-3)(x+3)}$ =0
⇔ $-(x+2)^{2}$ = 0
⇔ x = -2