Đáp án:
`1.`
`\sqrt(1^3+2^3+3^3)-\sqrt(1,8.3,2)`
`=\sqrt(1+8+27)-\sqrt(5,76)`
`=\sqrt(36)-2,4=6-2,4=3,6`
`2.`
`(2^12 . 5^7+4^6 . 25^3)/(8^5 . 25^3 +(2^2 . 5)^6`
`=(2^12 . 5^7 + (2^2)^6 . (5^2)^3)/((2^3)^5 . (5^2)^3 +2^12 . 5^6)=(2^12 . 5^7+2^12 . 5^6)/(2^15 . 5^6+2^12 . 5^6)`
`=(2^12 . 5^6 . (5+1))/(2^12 . 5^6 . (2^3 + 1))=(2^12 . 5^6 . 6)/(2^12 . 5^6 . 9)=6/9=2/3`
