Đáp án:
c) \(x > \dfrac{3}{2}\)
Giải thích các bước giải:
\(\begin{array}{l}
c){\left( {x - 2} \right)^2} < {\left( {x - 1} \right)^2}\\
\to {\left( {x - 2} \right)^2} - {\left( {x - 1} \right)^2} < 0\\
\to \left( {x - 2 - x + 1} \right)\left( {x - 2 + x - 1} \right) < 0\\
\to - \left( {2x - 3} \right) < 0\\
\to 2x - 3 > 0\\
\to x > \dfrac{3}{2}\\
d)4{x^2} - 4x + 1 - 4{x^2} - x + 3 \ge 5\\
\to - 5x \ge 1\\
\to x \le - \dfrac{1}{5}
\end{array}\)
