Đáp án:
2) x=-4
Giải thích các bước giải:
\(\begin{array}{l}
2)\left( {x + \dfrac{{11}}{2}} \right).\dfrac{7}{3} = \dfrac{1}{2} + 3\\
\to \left( {x + \dfrac{{11}}{2}} \right).\dfrac{7}{3} = \dfrac{7}{2}\\
\to x + \dfrac{{11}}{2} = \dfrac{3}{2}\\
\to x = - 4\\
4)\left( {\dfrac{3}{4}x - \dfrac{{21}}{2}} \right):3 = \dfrac{{15}}{8}.\dfrac{4}{5}\\
\to \left( {\dfrac{3}{4}x - \dfrac{{21}}{2}} \right):3 = \dfrac{3}{2}\\
\to \dfrac{3}{4}x - \dfrac{{21}}{2} = \dfrac{9}{2}\\
\to \dfrac{3}{4}x = 15\\
\to x = 20\\
6)2x + \dfrac{1}{4} = \dfrac{5}{3} - \dfrac{2}{3}\\
\to 2x + \dfrac{1}{4} = 1\\
\to 2x = \dfrac{3}{4}\\
\to x = \dfrac{3}{8}\\
8)\dfrac{{31}}{{15}}:\left( { - \dfrac{7}{3} - 3x} \right) = - \dfrac{{18}}{5}\\
\to - \dfrac{7}{3} - 3x = - \dfrac{{31}}{{54}}\\
\to 3x = - \dfrac{{95}}{{54}}\\
\to x = - \dfrac{{95}}{{162}}
\end{array}\)
