Đáp án+Giải thích các bước giải:
`ĐKXĐ:x\ne -2;x\ne -3`
`\frac{5(x-2)}{x+2}-\frac{2(x-3)}{x+3}=3`
`<=>\frac{5(x-2)(x+3)}{(x+2)(x+3)}-\frac{2(x-3)(x+2)}{(x+2)(x+3)}=\frac{3(x+3)(x+2)}{(x+2)(x+3)}`
`=>5(x-2)(x+3)-2(x-3)(x+2)=3(x+3)(x+2)`
`<=>5(x^2+3x-2x-6)-2(x^2+2x-3x-6)=3(x^2+2x+3x+6)`
`<=>5(x^2+x-6)-2(x^2-x-6)=3(x^2+5x+6)`
`<=>5x^2+5x-30-2x^2+2x+12=3x^2+15x+18`
`<=>3x^2+7x-18=3x^2+15x+18`
`<=>3x^2+7x-18-3x^2-15x-18=0`
`<=>-8x-36=0`
`<=>-8x=36`
`<=>x=-36/8(TM)`
Vậy `S=\{-9/2\}`
