`(2-3x)(2x -5x+6)<0 `
`⇔` `(2-3x)(-3x+6)<0 `
`⇔` `-24x+12+9x^{2}<0`
`⇒` `-24x+12+9x^{2}=0`
`⇒` `x=` `\frac{-(-24)±\sqrt[(-24)^{2}-4.9.12]}{2.9}`
`⇒` `x=\frac{24±12}{18}`
`⇒` \(\left[ \begin{array}{l}x=2\\x=\frac{2}{3}\end{array} \right.\)
`⇒` `9(x-2)``(x-\frac{2}{3})<0`
TH`1:` `x-2>0`
`x-\frac{2}{3}<0`
`⇒` `x∈∅`
TH`2:` `x-2<0`
`x-\frac{2}{3}>0`
`⇒` `x∈` `{\frac{2}{3};2}`
Vậy `:` `x∈` `{\frac{2}{3};2}`
