Em tham khảo nha:
\(\begin{array}{l}
1)\\
{({C_6}{H_{12}}{O_6})_n} \xrightarrow{\text{ lên men }} 2n{C_2}{H_5}OH + 2nC{O_2}\\
{C_2}{H_5}OH \xrightarrow{t^0,xt} {C_2}{H_4} + {H_2}O\\
{C_2}{H_4} + {H_2}O \xrightarrow{t^0,xt} {C_2}{H_5}OH\\
CuO + {C_2}{H_5}OH \xrightarrow{t^0} Cu + {H_2}O + C{H_3}CHO\\
2)\\
a)\\
{C_6}{H_5}OH + B{r_2} \to {C_6}{H_2}OHB{r_3} + 3HBr\\
b)\\
{n_{{C_6}{H_2}OHB{r_3}}} = \dfrac{{16,55}}{{331}} = 0,05\,mol\\
{n_{{C_6}{H_5}OH}} = {n_{{C_6}{H_2}OHB{r_3}}} = 0,05\,mol\\
{m_{{C_6}{H_5}OH}} = 0,05 \times 94 = 4,7g\\
{m_{{C_2}{H_5}OH}} = 13,9 - 4,7 = 9,2g\\
c)\\
2{C_6}{H_5}OH + 2Na \to 2{C_6}{H_5}ONa + {H_2}\\
{n_{{H_2}}} = \dfrac{{0,05}}{2} = 0,025\,mol\\
{V_{{H_2}}} = 0,025 \times 22,4 = 0,56l
\end{array}\)
