Đáp án:
`B-A=(-3)/2`
Giải thích các bước giải:
`A=3^1+3^2+3^3+...+3^2012`
`=>3A=3(3^1+3^2+3^3+...+3^2012)`
`=>3A=3^2+3^3+3^4+...+3^2013`
`=>3A-A=(3^2+3^3+3^4+...+3^2013)-(3^1+3^2+3^3+...+3^2012)`
`=>2A=3^2013-3`
`=>A={3^2013-3}/2`
`=>B-A=(3^2013)/2 - (3^2013 -3)/2`
`=>B-A= (3^2013 - 3^2013 - 3)/2`
`=>B-A=(0-3)/2=(-3)/2`
Vậy `B-A=(-3)/2`