Giải thích các bước giải:
$\dfrac{2^{12}.3^5+12^8}{2^{12}.27^3+8^3.3^8}$
$=\dfrac{2^{12}.3^5+(3.2^2)^8}{2^{12}.(3^3)^3+(2^3)^3.3^8}$
$=\dfrac{2^{12}.3^5+3^8.2^{16}}{2^{12}.3^9+2^9.3^8}$
$=\dfrac{2^{9}.3^5(2^3+3^3.2^{7})}{2^{9}.3^5(2^3.3^4+3^3)}$
$=\dfrac{2^3+3^3.2^{7}}{2^3.3^4+3^3}$