`~rai~`
\(2x^2-x=0\\\Leftrightarrow x(2x-1)=0\\\Leftrightarrow \left[\begin{array}{I}x=0\\2x-1=0\end{array}\right.\\\Leftrightarrow \left[\begin{array}{I}x=0\\2x=1\end{array}\right.\\\Leftrightarrow \left[\begin{array}{I}x=0\\x=\dfrac{1}{2}.\end{array}\right.\\\text{Vậy }x\in\left\{0;\dfrac{1}{2}\right\}.\)
Giải thích các bước giải:
`2x^2-x=0`
`<=>x(2x-1)=0`
`<=>`\(\left[ \begin{array}{l}x=0\\2x-1=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=0\\2x=1\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=0\\x=\dfrac{1}{2} \end{array} \right.\)
Vậy tập nghiệm của phương trình là `S={0;1/2}`
các bạn hộ mình với ạ plssss =((
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