Đáp án:
Giải thích các bước giải:
${(x-\dfrac{2}{3})^2}$ = $\dfrac{9}{4}$
${(x-\dfrac{2}{3})^2}$ = $\dfrac{3²}{2²}$
${(x-\dfrac{2}{3})^2}$ = $(\dfrac{±3}{2})²$
TH1:
${x-\dfrac{2}{3}}$ = $\dfrac{3}{2}$
$x = \dfrac{3}{2} + \dfrac{2}{3}$
x = $\dfrac{13}{6}$
Th2 :
${x-\dfrac{2}{3}}$ = $\dfrac{-3}{2}$
$x = \dfrac{-3}{2} + \dfrac{2}{3}$
x = $\dfrac{-5}{6}$
