\(\left|x-2\right|+x=3\)
\(\left|x+2\right|=3-x\)
\(\Rightarrow\left\{{}\begin{matrix}x-2=3-x\\x-2=\left(-3\right)-x\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x+x=3+2\\x+x=\left(-3\right)+2\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}2x=5\\2x=-1\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5}{2}\\x=\dfrac{-1}{2}\end{matrix}\right.\)
Vậy \(x\in\left\{\dfrac{5}{2};\dfrac{-1}{2}\right\}\)
