X+2 + x+4 = x+6 + x+8 98 96 94 92 giúp em với ạ

buikimvietha2005

2 năm trước

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duonghuy1699

Đáp án + Giải thích các bước giải:

`(x+2)/(98)+(x+4)/(96)=(x+6)/(94)+(x+8)/(92)`

`<=>((x+2)/(98)+1)+((x+4)/(96)+1)=((x+6)/(94)+1)+((x+8)/(92)+1)`

`<=>((x+2)/(98)+(98)/(98))+((x+4)/(96)+(96)/(96))=((x+6)/(94)+(94)/(94))+((x+8)/(92)+(92)/(92))`

`<=>(x+100)/(98)+(x+100)/(96)=(x+100)/(94)+(x+100)/(92)`

`<=>(x+100)/(98)+(x+100)/(96)-(x+100)/(94)-(x+100)/(92)=0`

`<=>(x+100)((1)/(98)+(1)/(96)-(1)/(94)-(1)/(92))=0`

`<=>x+100=0` . Vì `(1)/(98)+(1)/(96)-(1)/(94)-(1)/(92)\ne0`

`<=>x=-100`

Vote (0) Phản hồi (0) 2 năm trước

thao912

`(x+2)/98+(x+4)/96=(x+6)/94+(x+8)/92`

`↔((x+2)/98+1)+((x+4)/96+1)=((x+6)/94+1)+((x+8)/92+1)`

`↔(x+100)/98+(x+100)/96=(x+100)/94+(x+100)/92`

`↔(x+100)/98+(x+100)/96-(x+100)/94-(x+100)/92=0`

`↔(x+100)(1/98+1/96-1/94-1/92)=0`

Do `1/98+1/96-1/94-1/92\ne0` nên:

`→x+100=0`

`↔x=-100`

Vậy `x=-100`

Vote (0) Phản hồi (0) 2 năm trước

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