Theo đề ta có:
(2x+5).|-7|=73
=> \(\left[{}\begin{matrix}\left(2x+5\right).7=73\\\Rightarrow\left(2x+5\right)=\dfrac{73}{7}\\\Rightarrow2x=\dfrac{73}{7}-5\\\Rightarrow2x=\dfrac{73}{7}-\dfrac{35}{7}\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}2x=\dfrac{38}{7}\\\Rightarrow x=\dfrac{38}{7}:2\\\Rightarrow x=\dfrac{19}{7}\end{matrix}\right.\)
