Đáp án:
Giải thích các bước giải:
\[\frac{{{{\left( { - 2} \right)}^{18}}{{.8}^{15}}{{.16}^4}}}{{{{32}^{16}}}} = \frac{{{{\left( { - 2} \right)}^{18}}{{.8}^{15}}{{.8}^4}{{.2}^4}}}{{{8^{16}}{{.4}^{16}}}} = \frac{{{{\left( { - 2} \right)}^{18}}{{.2}^4}{{.8}^{19}}}}{{{8^{16}}{{.2}^{32}}}} = \frac{{{2^{22}}{{.8}^3}}}{{{2^{32}}}} = \frac{{{2^{31}}}}{{{2^{32}}}} = \frac{1}{2}\]