$\text{Đáp án:}$
$(2\dfrac{1}{3}+3\dfrac{1}{2})×0,2+25%$
$=(\dfrac{7}{3}+\dfrac{7}{2})×\dfrac{1}{5}+\dfrac{1}{4}$
$=\dfrac{7×2+7×3}{6}×\dfrac{1}{5}+\dfrac{1}{4}$
$=\dfrac{35}{6}×\dfrac{1}{5}+\dfrac{1}{4}$
$=\dfrac{7}{6}+\dfrac{1}{4}$
$=\dfrac{7×2+3}{12}$
$=\dfrac{17}{12}$