$a$) $2(x-1) =3x$
$⇔ 2x - 2 = 3x$
$⇔ 2x - 3x = -2$
$⇔ -x = 2$
$⇔ x = -2$
Vậy $x=-2$
$b$) $-3(x-1) = 2(1+x)$
$⇔ 3(1-x) = 2(1+x)$
$⇔ 3 - 3x = 2 + 2x$
$⇔ 2x + 3x = 3 - 2$
$⇔ 5x = 1$
$⇔ x = \dfrac{1}{5}$
Vậy `x=1/5`
$c$) $-5(x+3) - x+2 = 5$
$⇔ -5x - 15 - x + 2 = 5$
$⇔ -6x = 18$
$⇔ x = -3$
Vậy $x=-3$.
$d$) $-3(x-4) + 2(x+2) = -4$
$⇔ -3x + 12 + 2x + 4 = -4$
$⇔ -x = -20$
$⇔ x = 20$
Vậy `x=20`.