Đáp án:
480 g
Giải thích các bước giải:
${C_6}{H_{12}}{O_6}\xrightarrow{{men}}2{C_2}{H_5}OH + 2C{O_2}$
$\begin{gathered}
{V_{{C_2}{H_5}OH}} = \dfrac{{500.46}}{{100}} = 230ml \hfill \\
\Rightarrow {m_{{C_2}{H_5}OH}} = D.V = 230.0,8 = 184g \hfill \\
\Rightarrow {n_{{C_2}{H_5}OH}} = \dfrac{{184}}{{46}} = 4mol \hfill \\
\Rightarrow {n_{{C_6}{H_{12}}{O_6}(pu)}} = \dfrac{1}{2}{n_{{C_2}{H_5}OH}} = 2mol \hfill \\
H = 75\% \Rightarrow {n_{{C_6}{H_{12}}{O_6}(tt)}} = \dfrac{2}{H} = \dfrac{2}{{75\% }} = \dfrac{8}{3}mol \hfill \\
\Rightarrow {m_{{C_6}{H_{12}}{O_6}}} = \frac{8}{3}.180 = 480g \hfill \\
\end{gathered} $
